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What is the domain of (f(x)=\sqrt{\frac{9-x^2}{x^2-4}})?फलन (f(x)=\sqrt{\frac{9-x^2}{x^2-4}}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-3,-2)\cup(2,3] )( [-3,-2)\cup(2,3] )
The square root needs (\frac{9-x^2}{x^2-4}\ge 0) and (x\ne\pm2). A sign check gives ([-3,-2)\cup(2,3]).वर्गमूल के अंदर (\frac{9-x^2}{x^2-4}\ge 0) और (x\ne\pm2) चाहिए। संकेत जांच से ([-3,-2)\cup(2,3]) मिलता है।
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