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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeExpert

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What is the range of (f(x)=\frac{x^2+9}{3x})?

Answer and explanation

Correct answer: ( (-\infty,-2]\cup[2,\infty) )

Here (f(x)=\frac{x}{3}+\frac{3}{x}). For positive (x), the minimum is (2), and for negative (x), the maximum is (-2).

Related tags

Real-Valued-Functions Range Rational Am-Gm Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics

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