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What is the range of \(f(x)=\sin x\) when \(x\in\left[0,\frac{3\pi}{2}\right]\)?फलन \(f(x)=\sin x\) का परिसर क्या है, जब \(x\in\left[0,\frac{3\pi}{2}\right]\)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-1,1] )( [-1,1] )
In the given interval, (\sin x) attains both maximum (1) and minimum (-1). For trigonometric ranges, check key angles.दिए गए अंतराल में (\sin x) का अधिकतम (1) और न्यूनतम (-1) दोनों आते हैं। त्रिकोणमितीय परिसर के लिए प्रमुख कोणों की जांच करें।
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