What is the range of (f(x)=\sqrt{x-2}+\sqrt{7-x})?फलन (f(x)=\sqrt{x-2}+\sqrt{7-x}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [\sqrt{5},\sqrt{10}] )( [\sqrt{5},\sqrt{10}] )
At the endpoints the value is (\sqrt{5}), and at the midpoint (x=\frac{9}{2}), the maximum is (\sqrt{10}). In symmetric questions, always check the midpoint.सिरों पर मान (\sqrt{5}) और मध्य (x=\frac{9}{2}) पर अधिकतम (\sqrt{10}) है। सममिति वाले प्रश्नों में मध्य बिंदु जरूर जांचें।
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