If (f(x)=-x^2+6x-5), what is the range of (f)?यदि (f(x)=-x^2+6x-5), तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-\infty,4] )( (-\infty,4] )
Here (f(x)=-(x-3)^2+4), so the maximum is (4). A downward-opening parabola has range ((-\infty,\text{maximum}]).(f(x)=-(x-3)^2+4), इसलिए अधिकतम (4) है। नीचे खुलने वाले परवलय का परिसर ((-\infty,\text{अधिकतम}]) होता है।
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