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What is the domain of (f(x)=\frac{x^2-16}{x-4})?फलन (f(x)=\frac{x^2-16}{x-4}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}\setminus{4} )( \mathbb{R}\setminus{4} )
The original denominator is (x-4), so (x=4) is not allowed. Even after simplification, do not add the removed point to the domain.मूल हर (x-4) है, इसलिए (x=4) स्वीकार्य नहीं है। सरलीकरण के बाद भी हटे बिंदु को प्रांत में न जोड़ें।
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