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What is the range of (f(x)=\frac{\sqrt{x-1}}{\sqrt{x-1}+4})?फलन (f(x)=\frac{\sqrt{x-1}}{\sqrt{x-1}+4}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [0,1) )( [0,1) )
Put (t=\sqrt{x-1}\ge 0), then (f=\frac{t}{t+4}). At (t=0), the value is (0), and as (t\to\infty), it approaches (1).(t=\sqrt{x-1}\ge 0) रखने पर (f=\frac{t}{t+4})। (t=0) पर (0) मिलता है और (t\to\infty) पर मान (1) के पास जाता है।
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