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What is the range of (f(x)=\frac{7x+4}{2x-3})?फलन (f(x)=\frac{7x+4}{2x-3}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}\setminus{\frac{7}{2}} )( \mathbb{R}\setminus{\frac{7}{2}} )
From (y=\frac{7x+4}{2x-3}), (x=\frac{3y+4}{2y-7}), so (y\ne \frac{7}{2}). In a linear fractional function, remove the impossible (y).(y=\frac{7x+4}{2x-3}) से (x=\frac{3y+4}{2y-7}), इसलिए (y\ne \frac{7}{2})। रैखिक भिन्न फलन में असंभव (y) को हटाएं।
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