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What is the range of (f(x)=\sqrt{x^2-6x+5})?फलन (f(x)=\sqrt{x^2-6x+5}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [0,\infty) )( [0,\infty) )
On the domain, the inside expression starts at (0) and goes to infinity. Hence the square root range is ([0,\infty)).प्रांत में अंदर का व्यंजक (0) से शुरू होकर असीम तक जाता है। इसलिए वर्गमूल का परिसर ([0,\infty)) है।
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