If (f(x)=\sqrt{x-1}+\sqrt{9-x}), what is the range of (f)?यदि (f(x)=\sqrt{x-1}+\sqrt{9-x}), तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [2\sqrt{2},4] )( [2\sqrt{2},4] )
At the endpoints the value is (2\sqrt{2}), and at the midpoint (x=5), the maximum is (4). For symmetric radicals, check both endpoints and the midpoint.सिरों पर मान (2\sqrt{2}) और मध्य (x=5) पर अधिकतम (4) है। सममित वर्गमूलों में सिरों और मध्य दोनों जांचें।
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