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What is the range of (f(x)=\frac{2x}{x^2+1})?फलन (f(x)=\frac{2x}{x^2+1}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-1,1] )( [-1,1] )
(|2x|\le x^2+1) because ((x-1)^2\ge 0) and ((x+1)^2\ge 0). Hence the values lie from (-1) to (1), and both occur.(|2x|\le x^2+1) क्योंकि ((x-1)^2\ge 0) और ((x+1)^2\ge 0)। इसलिए मान (-1) से (1) तक हैं और दोनों मिलते हैं।
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