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What is the domain of (f(x)=\frac{x^2-9}{x-3})?फलन (f(x)=\frac{x^2-9}{x-3}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}\setminus{3} )( \mathbb{R}\setminus{3} )
The original denominator is (x-3), so (x=3) is not allowed. Even after simplification, do not add the removed point to the domain.मूल हर (x-3) है, इसलिए (x=3) स्वीकार्य नहीं है। सरलीकरण के बाद भी हटे हुए बिंदु को प्रांत में न जोड़ें।
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