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What is the range of (f(x)=\frac{x^2-9}{x-3})?फलन (f(x)=\frac{x^2-9}{x-3}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}\setminus{6} )( \mathbb{R}\setminus{6} )
The original domain has (x\ne 3), and simplification gives (f(x)=x+3). Hence the value (6), which would occur at (x=3), is excluded from the range.मूल प्रांत में (x\ne 3) है और सरलीकरण से (f(x)=x+3)। इसलिए (x=3) पर आने वाला मान (6) परिसर से हटेगा।
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