0 reads0 ratings0 helpful
What is the range of (f(x)=\frac{3x^2+1}{x^2+1})?फलन (f(x)=\frac{3x^2+1}{x^2+1}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [1,3) )( [1,3) )
Put (t=x^2\ge 0), then (f=\frac{3t+1}{t+1}=3-\frac{2}{t+1}). At (t=0), the value is (1), and (3) is only a limiting value.(t=x^2\ge 0) रखने पर (f=\frac{3t+1}{t+1}=3-\frac{2}{t+1})। (t=0) पर (1) मिलता है और (3) केवल सीमा मान है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
