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What is the range of \(f(x)=\sqrt{(x+2)(5-x)}\)?फलन \(f(x)=\sqrt{(x+2)(5-x)}\) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \( [0,\frac{7}{2}] \)\( [0,\frac{7}{2}] \)
\((x+2)(5-x)=\frac{49}{4}-\left(x-\frac{3}{2}\right)^2\) has maximum \(\frac{49}{4}\). The square root gives maximum \(\frac{7}{2}\) and minimum (0).\((x+2)(5-x)=\frac{49}{4}-\left(x-\frac{3}{2}\right)^2\) का अधिकतम \(\frac{49}{4}\) है। वर्गमूल से अधिकतम \(\frac{7}{2}\) और न्यूनतम (0) मिलता है।
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