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What is the domain of (f(x)=\sqrt{\frac{x-3}{x+1}})?फलन (f(x)=\sqrt{\frac{x-3}{x+1}}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-\infty,-1)\cup[3,\infty) )( (-\infty,-1)\cup[3,\infty) )
The expression inside the square root must satisfy (\frac{x-3}{x+1}\ge 0) and (x\ne -1). A sign chart gives (x<-1) or (x\ge 3).वर्गमूल के अंदर (\frac{x-3}{x+1}\ge 0) और (x\ne -1) चाहिए। संकेत सारणी से (x<-1) या (x\ge 3) मिलता है।
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