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What is the range of (f(x)=\frac{x^2}{x^2-4})?फलन (f(x)=\frac{x^2}{x^2-4}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-\infty,0]\cup(1,\infty) )( (-\infty,0]\cup(1,\infty) )
Put (t=x^2\ge 0) and (t\ne 4). Then (f=\frac{t}{t-4}), giving ((-\infty,0]) for (t\in[0,4)) and ((1,\infty)) for (t>4).मान (t=x^2\ge 0) रखें और (t\ne 4)। तब (f=\frac{t}{t-4}), जिससे (t\in[0,4)) पर ((-\infty,0]) और (t>4) पर ((1,\infty)) मिलता है।
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