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What is the range of (f(x)=\frac{4x}{x^2+4})?फलन (f(x)=\frac{4x}{x^2+4}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-1,1] )( [-1,1] )
(|4x|\le x^2+4) because ((x-2)^2\ge 0) and ((x+2)^2\ge 0). Hence values lie from (-1) to (1), and both endpoints occur.(|4x|\le x^2+4) क्योंकि ((x-2)^2\ge 0) और ((x+2)^2\ge 0)। इसलिए मान (-1) से (1) तक हैं और दोनों मिलते हैं।
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