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If f(x) = 3/(2 − √x), what is its domain?

Answer and explanation

Correct answer: [0, ∞) \ {4}

The domain must satisfy two independent conditions. First, the square root √x is real only when x ≥ 0. Second, the denominator cannot be zero, so 2 − √x ≠ 0. Solving the second condition gives √x ≠ 2, and therefore x ≠ 4. Combining these restrictions produces [0, ∞) with the single point 4 removed. Notice that x = 0 is allowed: the denominator is then 2, not zero. Values greater than 4 are also allowed, although the denominator becomes negative; a negative denominator is perfectly valid. Thus option A is correct. Option B wrongly excludes all x ≥ 4, option C incorrectly removes 0, and option D includes negative numbers for which the square root is not real.

Related tags

Relations-FunctionsReal-Valued-FunctionsDomainRadicalReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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