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What is the domain of (f(x)=\frac{\sqrt{x+1}}{x^2-4})?फलन (f(x)=\frac{\sqrt{x+1}}{x^2-4}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-1,\infty)\setminus{2} )( [-1,\infty)\setminus{2} )
The square root needs (x\ge -1), and the denominator needs (x\ne \pm 2). Since (-2) is already outside the domain, only (2) is removed.वर्गमूल के लिए (x\ge -1) और हर के लिए (x\ne \pm 2) चाहिए। (-2) पहले से प्रांत में नहीं है, इसलिए केवल (2) हटेगा।
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