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If (f(x)=\frac{2x^2+3}{x^2+1}), what is the range of (f)?यदि (f(x)=\frac{2x^2+3}{x^2+1}), तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((2,3])((2,3])
Let (t=x^2\ge 0), then (f=\frac{2t+3}{t+1}) is decreasing. At (t=0), (3) is obtained and (2) is not attained.मान लें (t=x^2\ge 0), तब (f=\frac{2t+3}{t+1}) घटता है। (t=0) पर (3) मिलता है और (2) प्राप्त नहीं होता।
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