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What is the maximum value of f(x) = 1/(x^2 + 2x + 2)?

Answer and explanation

Correct answer: 1

Complete the square in the denominator: x^2 + 2x + 2 = (x + 1)^2 + 1. Since (x + 1)^2 is always non-negative, the denominator is at least 1, with equality when x = −1. The denominator is therefore positive and has its minimum value 1. For a positive reciprocal, the largest value occurs when the denominator is smallest. Consequently f(−1) = 1/1 = 1, so the maximum value is 1. Option A is correct. The value 1/2 would arise only if the denominator had minimum 2, which it does not; 2 is not the maximum, and 0 is approached only as the denominator grows without bound, not attained as the maximum.

Related tags

Real-Valued-FunctionsMaximumCompleting-The-SquareRangeReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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