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Find the range of (f(x)=\frac{x-2}{x+5}).फलन (f(x)=\frac{x-2}{x+5}) का परिसर ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}-{1})(\mathbb{R}-{1})
If (y=\frac{x-2}{x+5}), then (x=\frac{-5y-2}{y-1}), so (y\ne 1). Hence the range is (\mathbb{R}-{1}).यदि (y=\frac{x-2}{x+5}), तो (x=\frac{-5y-2}{y-1}), इसलिए (y\ne 1)। अतः परिसर (\mathbb{R}-{1}) है।
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