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Subjects
Class 11MathematicsRelations and FunctionsReal-Valued Functions, Their Domain and RangeHard
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If (f(x)=x+\frac{4}{x}), (x<0), choose the range of (f).

Answer and explanation

Correct answer: ((-\infty,-4])

For negative (x), put (x=-t), (t>0), then (f=-(t+\frac{4}{t})\le -4). Hence the range is ((-\infty,-4]).

Related tags

Relations-FunctionsRangeNegative-DomainReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematicsClass 11 Mcq
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10 more MCQs
  1. 1If A = {1,2,3} and R = {(1,2),(2,3)}, which element is in the domain of R but not in its range?
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  4. 4What is the range of the relation \(R=\{(x,y): y=x^2,\ x\in\{-2,-1,0,1,2\}\}\)?
  5. 5If \(f:A\to B\) is a function, what is \(A\) called?
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  7. 7What is the domain of the function \(f=\{(2,4),(3,9),(4,16)\}\)?
  8. 8If \(f(x)=x+2\) and its domain is \(\{1,2,3\}\), what is the value of \(f(2)\)?
  9. 9If \(f(x)=x-1\) and \(A=\{2,3,4\}\), what is \(f(A)\)?
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