0 reads0 ratings0 helpful
Which of the following is the correct pair of domain and range for \(f(x)=\sqrt{x^2+1}\)?फलन \(f(x)=\sqrt{x^2+1}\) के प्रांत और परास का सही युग्म कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\mathbb R,\ [1,\infty)\)\(\mathbb R,\ [1,\infty)\)
Since \(x^2\ge0\), we get \(x^2+1\ge1\) for every real \(x\). Hence the domain is \(\mathbb R\) and the range is \([1,\infty)\). Option B wrongly includes 0. Exam tip: a square root always denotes the non-negative principal value.क्योंकि \(x^2\ge0\), इसलिए \(x^2+1\ge1\) हर वास्तविक \(x\) के लिए है; अतः प्रांत \(\mathbb R\) और परास \([1,\infty)\) है। विकल्प B में न्यूनतम मान 0 मानना गलत है। परीक्षा टिप: वर्गमूल का मुख्य मान अऋणात्मक होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
