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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeHard

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If (f(x)=\sqrt{\frac{x-1}{x+2}}), which is the domain?

Answer and explanation

Correct answer: ((-\infty,-2)\cup[1,\infty))

The condition is (\frac{x-1}{x+2}\ge 0) and (x\ne -2). A sign chart gives ((-\infty,-2)\cup[1,\infty)).

Related tags

Relations-Functions Domain Sign-Chart Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics Class 11 Mcq

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