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What is the range of (f(x)=\frac{2x+1}{x-3})?फलन (f(x)=\frac{2x+1}{x-3}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}-{2})(\mathbb{R}-{2})
If (y=\frac{2x+1}{x-3}), then (x=\frac{3y+1}{y-2}), so (y\ne 2). Hence the range is (\mathbb{R}-{2}).यदि (y=\frac{2x+1}{x-3}), तो (x=\frac{3y+1}{y-2}), अतः (y\ne 2)। इसलिए परिसर (\mathbb{R}-{2}) है।
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