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If (f(x)=\frac{\sqrt{(x-2)(7-x)}}{x^2-9}), what is the domain of (f)?यदि (f(x)=\frac{\sqrt{(x-2)(7-x)}}{x^2-9}) है तो (f) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [2,3)\cup(3,7] )( [2,3)\cup(3,7] )
For the square root, ((x-2)(7-x)\ge0) gives (x\in[2,7]), and the denominator removes (x=3). Taking the intersection of all restrictions is essential.वर्गमूल के लिए ((x-2)(7-x)\ge0) से (x\in[2,7]) मिलता है और हर से (x\ne3) हटेगा। संयुक्त प्रतिबंधों का प्रतिच्छेद लेना जरूरी है।
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