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If (f(x)=\sqrt{x-1}+\sqrt{x-4}), what is the range of (f)?यदि (f(x)=\sqrt{x-1}+\sqrt{x-4}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [\sqrt{3},\infty) )( [\sqrt{3},\infty) )
The domain is (x\ge4), and at (x=4) the value is (\sqrt{3}). Both terms increase, so this is the minimum.प्रांत (x\ge4) है और (x=4) पर मान (\sqrt{3}) मिलता है। दोनों पद बढ़ते हैं इसलिए यही न्यूनतम है।
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