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If (f(x)=\frac{x^2-1}{x^2+1}), what is the range of (f)?यदि (f(x)=\frac{x^2-1}{x^2+1}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-1,1) )( [-1,1) )
Here (f(x)=1-\frac{2}{x^2+1}), so the minimum is (-1), and the upper bound (1) is not attained. Rewriting the expression quickly gives the range.(f(x)=1-\frac{2}{x^2+1}) है इसलिए न्यूनतम (-1) और ऊपरी सीमा (1) अप्राप्त है। रूप बदलकर परिसर जल्दी मिलता है।
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