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What is the maximum value of (f(x)=\sqrt{x}+\sqrt{6-x})?फलन (f(x)=\sqrt{x}+\sqrt{6-x}) का अधिकतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2\sqrt{3})(2\sqrt{3})
By symmetry the maximum occurs at (x=3), and the value is (2\sqrt{3}). In such forms try making the two terms equal.सममिति के कारण अधिकतम (x=3) पर है और मान (2\sqrt{3}) है। ऐसे रूप में दोनों पद बराबर करने की कोशिश करें।
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