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What is the range of (f(x)=\frac{1}{x^2-6x+10})?फलन (f(x)=\frac{1}{x^2-6x+10}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (0,1] )( (0,1] )
The denominator ((x-3)^2+1\ge1), so the maximum is (\frac{1}{1}=1), and (0) is not attained. Completing the square gives the bounds clearly.हर ((x-3)^2+1\ge1) है इसलिए अधिकतम (\frac{1}{1}=1) है और (0) प्राप्त नहीं होता। पूर्ण वर्ग से सीमा साफ मिलती है।
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