What is the domain of (f(x)=\sqrt{x^2-4x+3})?फलन (f(x)=\sqrt{x^2-4x+3}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-\infty,1]\cup[3,\infty) )( (-\infty,1]\cup[3,\infty) )
Since (x^2-4x+3=(x-1)(x-3)), it must be (\ge0). For an upward quadratic, the outside intervals are selected.(x^2-4x+3=(x-1)(x-3)) और इसे (\ge0) चाहिए। ऊपर खुलने वाले द्विघात में बाहरी अंतराल चुने जाते हैं।
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