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What is the domain of (f(x)=\sqrt{x^2-4x+3})?

Answer and explanation

Correct answer: ( (-\infty,1]\cup[3,\infty) )

Since (x^2-4x+3=(x-1)(x-3)), it must be (\ge0). For an upward quadratic, the outside intervals are selected.

Related tags

Relations-FunctionsDomain-RangeHardLevel-32Real Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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