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What is the range of (f(x)=\frac{x-1}{x+2}) where (x\ne-2)?फलन (f(x)=\frac{x-1}{x+2}) का परिसर क्या है जहाँ (x\ne-2)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}\setminus{1} )( \mathbb{R}\setminus{1} )
From (y=\frac{x-1}{x+2}), we get (x=\frac{1+2y}{1-y}), so (y\ne1). Writing (x) in terms of (y) works well for range.(y=\frac{x-1}{x+2}) से (x=\frac{1+2y}{1-y}) मिलता है इसलिए (y\ne1)। परिसर के लिए (x) को (y) के रूप में लिखना कारगर है।
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