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What is the range of (f(x)=\frac{1}{x^2+4}) where (x\in\mathbb{R})?फलन (f(x)=\frac{1}{x^2+4}) का परिसर क्या है जहाँ (x\in\mathbb{R})?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (0,\frac{1}{4}] )( (0,\frac{1}{4}] )
Because (x^2+4\ge4), the maximum value is (\frac{1}{4}), and (0) is only approached. In exams do not close an unattained endpoint.क्योंकि (x^2+4\ge4), अधिकतम मान (\frac{1}{4}) है और (0) केवल निकट आता है। परीक्षा में असम्प्राप्त सीमा को बंद न करें।
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