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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeHard

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What is the domain of (f(x)=\frac{1}{\sqrt{|x-2|-3}})?

Answer and explanation

Correct answer: ((-\infty,-1)\cup(5,\infty))

The square root is in the denominator, so (|x-2|-3>0) is needed. This gives (|x-2|>3), so the domain is ((-\infty,-1)\cup(5,\infty)).

Related tags

Domain Absolute-Value Radical Denominator Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions Mathematics

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