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If (f(x)=\frac{x^2-9}{x^2+9}) and (x\in\mathbb{R}), what is the range of (f)?यदि (f(x)=\frac{x^2-9}{x^2+9}) और (x\in\mathbb{R}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-1,1))([-1,1))
Here (f(x)=1-\frac{18}{x^2+9}), and (x^2+9\ge 9). So the minimum value is (-1), and (1) is not attained.(f(x)=1-\frac{18}{x^2+9}) है और (x^2+9\ge 9) है। इसलिए न्यूनतम मान (-1) मिलता है और (1) प्राप्त नहीं होता।
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