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If (f(x)=\frac{x^2+1}{x^2+2}), what is the range of (f)?यदि (f(x)=\frac{x^2+1}{x^2+2}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{1}{2},1))([\frac{1}{2},1))
Here (f(x)=1-\frac{1}{x^2+2}) and (x^2+2\ge 2). Thus the minimum is (\frac{1}{2}) and (1) is not attained.(f(x)=1-\frac{1}{x^2+2}) और (x^2+2\ge 2) है। इसलिए न्यूनतम (\frac{1}{2}) है और (1) प्राप्त नहीं होता।
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