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What is the range of (f(x)=\frac{1}{|x+1|+2})?फलन (f(x)=\frac{1}{|x+1|+2}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,\frac{1}{2}])((0,\frac{1}{2}])
The denominator (|x+1|+2) has minimum (2) and can grow without bound. Thus the function is greater than (0) and at most (\frac{1}{2}).हर (|x+1|+2) का न्यूनतम (2) है और यह अनंत तक बढ़ सकता है। इसलिए फलन (0) से बड़ा और (\frac{1}{2}) तक है।
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