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If (f(x)=\frac{3}{x^2+2x+5}), what is the maximum value of (f)?यदि (f(x)=\frac{3}{x^2+2x+5}) है तो (f) का अधिकतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{3}{4})(\frac{3}{4})
The denominator (x^2+2x+5=(x+1)^2+4) has minimum value (4). A positive fraction is maximum when its denominator is minimum.हर (x^2+2x+5=(x+1)^2+4) का न्यूनतम मान (4) है। धनात्मक भिन्न का अधिकतम हर के न्यूनतम पर मिलता है।
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