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If (f(x)=\frac{x^2-1}{x-1}) and (x\ne 1), what is the range of (f)?यदि (f(x)=\frac{x^2-1}{x-1}) और (x\ne 1) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}\setminus{2})(\mathbb{R}\setminus{2})
Here (f(x)=x+1), but (x=1) is not allowed, so (y=2) is not obtained. After simplification, always track excluded domain values.(f(x)=x+1) है पर (x=1) अनुमत नहीं है इसलिए (y=2) नहीं मिलेगा। सरलीकरण के बाद हटाए गए प्रांत मान का प्रभाव जरूर देखें।
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