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If (f(x)=\frac{1}{x^2-6x+10}), what is the range of (f)?यदि (f(x)=\frac{1}{x^2-6x+10}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,1])((0,1])
The denominator (x^2-6x+10=(x-3)^2+1) is at least (1). Therefore the reciprocal is greater than (0) and at most (1).हर (x^2-6x+10=(x-3)^2+1) है इसलिए कम से कम (1) है। अतः व्युत्क्रम (0) से बड़ा और (1) तक होता है।
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