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Which of the following functions has all real numbers as its domain and \([0,1)\) as its range?

Answer and explanation

Correct answer: \(f(x)=\frac{x^2}{1+x^2}\)

For option A, put \(t=x^2\ge0\); then \(f=\frac{t}{1+t}\). It starts at 0 and approaches 1 without attaining it, so the range is \([0,1)\). Option C instead has range \((0,1]\). Exam tip: first check whether any denominator can be zero.

Related tags

Real Valued FunctionsDomain And RangeRational FunctionsClass 11 MathematicsRelations And FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeMathematics

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