0 reads0 ratings0 helpful
If (f(x)=\frac{x+2}{x-3}), what is the range of (f)?यदि (f(x)=\frac{x+2}{x-3}) है तो (f) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}\setminus{1})(\mathbb{R}\setminus{1})
From (y=\frac{x+2}{x-3}), (x=\frac{3y+2}{y-1}), so (y\ne 1). The range excludes the (y)-value that makes (x) undefined.(y=\frac{x+2}{x-3}) से (x=\frac{3y+2}{y-1}) मिलता है इसलिए (y\ne 1)। परिसर में वह (y) हटता है जिससे (x) परिभाषित न हो।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
