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If (f(x)=\frac{x^2}{x^2+1}) and (x\in\mathbb{R}), what is the range?यदि (f(x)=\frac{x^2}{x^2+1}) और (x\in\mathbb{R}) है तो परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([0,1))([0,1))
Here (f(x)=1-\frac{1}{x^2+1}), so values start at (0) and stay below (1). Check limiting values and attained values separately.(f(x)=1-\frac{1}{x^2+1}) है इसलिए मान (0) से शुरू होकर (1) से कम रहता है। सीमा मान और प्राप्त मान अलग-अलग जांचें।
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