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Class 11 Mathematics Relations and Functions Real-Valued Functions, Their Domain and RangeMedium

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For the real valued function (f(x)=\sqrt{9-x^2}), which option gives the correct domain and range?

Answer and explanation

Correct answer: Domain ( [-3,3] ), range ( [0,3] )

For (\sqrt{9-x^2}) to be real, (9-x^2\ge 0), so (x\in[-3,3]) and (f(x)\in[0,3]). In exams, always keep the expression inside a square root (\ge 0).

Related tags

Relations-Functions Real-Valued-Functions Domain-Range Square-Root-Function Class-11-Maths Real Valued Functions Their Domain And Range Real Valued Functions Their Domain And Range Relations And Functions

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