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If (f(x)=\sqrt{x^2-36}), what is (f(-10))?यदि (f(x)=\sqrt{x^2-36}) है, तो (f(-10)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
(f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.(f(-10)=\sqrt{100-36}=\sqrt{64}=8) है। परीक्षा में वर्गमूल की principal value non-negative होती है।
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