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Which statement is correct for (f(x)=\frac{1}{x^2-16})?कौन सा कथन (f(x)=\frac{1}{x^2-16}) के लिए सही है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Domain is (\mathbb{R}\setminus{-4,4})डोमेन (\mathbb{R}\setminus{-4,4}) है
The denominator (x^2-16) becomes (0) when (x=-4) or (x=4). In exams remove values that make the denominator (0).हर (x^2-16) तब (0) होता है जब (x=-4) या (x=4)। परीक्षा में denominator को (0) बनाने वाली values हटाएं।
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