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If (f(x)=\frac{1}{x+2}) and the domain is ([-6,-3]), what is the range?यदि (f(x)=\frac{1}{x+2}) और डोमेन ([-6,-3]) है, तो रेंज क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-1,-\frac{1}{4}])([-1,-\frac{1}{4}])
The value of (x+2) lies in ([-4,-1]), so the reciprocal gives ([-1,-\frac{1}{4}]). In exams handle the order carefully for negative denominators.(x+2) की वैल्यू ([-4,-1]) में है, इसलिए reciprocal ([-1,-\frac{1}{4}]) देता है। परीक्षा में ऋणात्मक denominator पर क्रम सावधानी से रखें।
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