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If (f(x)=\frac{1}{x-1}) and the domain is ([3,9]), what is the range?यदि (f(x)=\frac{1}{x-1}) और डोमेन ([3,9]) है, तो रेंज क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([\frac{1}{8},\frac{1}{2}])([\frac{1}{8},\frac{1}{2}])
On this domain the denominator is positive and the reciprocal decreases. (x=3) gives (\frac{1}{2}) and (x=9) gives (\frac{1}{8}).इस domain पर denominator धनात्मक है और reciprocal घटता है। (x=3) से (\frac{1}{2}) और (x=9) से (\frac{1}{8}) मिलता है।
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